Simple context menu problem

[Striped]

What's wrong with the context menu?

I have created one for the DataGrid control and showing it like this:

private void dataGrid_MouseUp(object sender,
System.Windows.Forms.MouseEventArgs e)
{
if( e.Button == MouseButtons.Right)
{
if( dataGrid.ContextMenu != null )
dataGrid.ContextMenu.Show(dataGrid, new Point(e.X, e.Y) );
}
}

The menu is displayed but I need to click TWICE to dismiss it!
Is it intended to be like that?

[Striped]

Never mind,
I just removed the right mouse click handler and everything is fine.
"Striped" <skovbasa[aatt]insycom.net> wrote in message
news:eX**************@tk2msftngp13.phx.gbl...

What's wrong with the context menu?

I have created one for the DataGrid control and showing it like this:

private void dataGrid_MouseUp(object sender,
System.Windows.Forms.MouseEventArgs e)
{
if( e.Button == MouseButtons.Right)
{
if( dataGrid.ContextMenu != null )
dataGrid.ContextMenu.Show(dataGrid, new Point(e.X, e.Y) );
}
}

The menu is displayed but I need to click TWICE to dismiss it!
Is it intended to be like that?

[Chris Jobson]

"Striped" <skovbasa[aatt]insycom.net> wrote in message
news:eX**************@tk2msftngp13.phx.gbl...

What's wrong with the context menu?

I have created one for the DataGrid control and showing it like this:

private void dataGrid_MouseUp(object sender,
System.Windows.Forms.MouseEventArgs e)
{
if( e.Button == MouseButtons.Right)
{
if( dataGrid.ContextMenu != null )
dataGrid.ContextMenu.Show(dataGrid, new Point(e.X, e.Y) );
}
}

The menu is displayed but I need to click TWICE to dismiss it!
Is it intended to be like that?

I believe that once the menu is assigned to the DataGrid's ContextMenu
property it will automatically be popped up in response to a right-mouse
click, so you don't need to handle the MouseUp event and show the menu
yourself.(I admit that this is NOT what the online help says, but it seems
to work!)

Chris Jobson